3 Replies Latest reply on Mar 3, 2011 3:05 PM by eugenek

    &a->b  is equal to &(a->n) ou (&a)->b

    spectral

      Hi,

       

      I suspect that sometimes the following expression "&a->b" is evaluated as :

      (&a)->b

       

      ... but it should be &(a->n) ? Right ?