is this possible?
Hi,
Assume that such simple kernel is given:
#pragma OPENCL EXTENSION cl_khr_byte_addressable_store : enable
__kernel void sum(__global const double2 *a,__global const float2 *b,__global float2 *c){
size_t id = get_global_id(0);
c[id]=a[id]+b[id];
} |
Running it on CPU works fine [implicit double to float cast performs] whereas on GPU it behaves quite unexpected. I suppose that implicit cast cannot be done in this case so I tried an explicit cast like
#pragma OPENCL EXTENSION cl_khr_byte_addressable_store : enable
__kernel void sum(__global const double2 *a,__global const float2 *b,__global float2 *c){
size_t id = get_global_id(0);
c[id].x = (float)a[id].x+b[id].x;
c[id].y = (float)a[id].y+b[id].y; //or even: float2 aa;
aa.x = a[id].x;
aa.x = a[id].x;
c[id].x = aa.x+b[id].x;
c[id].y = aa.y+b[id].y; } |
Both solutions are wrong - cause CL complier error or an undefined data as a result of such sum. I've also tried to use the to_float2(double2) function, but compliler complains that source and destination have different size. Does anyone have an idea why or how to avoid such issue? Is this possible at all to cast double -> float?
